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Equations for a function

1.[2p]

What makes a differential equation different from an algebraic equation?

Correct
The answer is: Its unknown is a function, so a solution is a whole curve rather than a number
The answer is: Its unknown is a function, so a solution is a whole curve rather than a number
The answer is: Its unknown is a function, so a solution is a whole curve rather than a number

2.[2p]

For the direction field of y'=t-y, what is the slope of the solution passing through the point t=3, y=1?

CorrectNot quite: 2

3.[2p]

Which of these equations is linear?

Correct
The answer is: $y' + t^2 y = \cos t$
The answer is: $y' + t^2 y = \cos t$
The answer is: $y' + t^2 y = \cos t$

4.[1p]

If y1 and y2 each solve y'=y2, then y1+y2 also solves it.

The answer is: False
Correct

5.[3p]

Carbon-14 has a half-life of 5730 years. A sample holds 40 per cent of its original carbon-14. How old is it, in years?

CorrectNot quite: 7575

6.[3p]

The general solution of y''+4y=0 is y=Acos2t+Bsin2t. For y(0)=5 and y'(0)=24, what is the amplitude A2+B2?

CorrectNot quite: 13

7.[3p]

Match each equation to its order and linearity.

  • y'=-kN

  • yy'=t

  • mx''+cx'+kx=0

  • θ''+sinθ=0

  • first order, linear

  • second order, nonlinear

  • second order, linear

  • first order, nonlinear

Show the answer

y'=-kN: first order, linear yy'=t: first order, nonlinear mx''+cx'+kx=0: second order, linear θ''+sinθ=0: second order, nonlinear

8.[3p]

Which statements about a direction field are correct?

Select all that apply

Correct
Correct
Correct
The answer is: It gives the slope of a solution at every point without any solving, A curve on which the slope takes one fixed value is called an isocline, Solutions are the curves that stay tangent to it everywhere

9.[2p]

A body falls under gravity with drag, obeying mdv/dt=mg-bv2. What can be read off the equation before solving it?

Correct
The answer is: The speed stops changing once $bv^2$ reaches $mg$, giving a terminal speed of $\sqrt{mg/b}$
The answer is: The speed stops changing once $bv^2$ reaches $mg$, giving a terminal speed of $\sqrt{mg/b}$
The answer is: The speed stops changing once $bv^2$ reaches $mg$, giving a terminal speed of $\sqrt{mg/b}$