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Autonomous equations and stability

1.[2p]

At an equilibrium y* of y'=f(y), what does f'(y*)<0 tell you?

Correct
The answer is: The equilibrium is stable, since a small displacement decays like $e^{f'(y^*)t}$
The answer is: The equilibrium is stable, since a small displacement decays like $e^{f'(y^*)t}$
The answer is: The equilibrium is stable, since a small displacement decays like $e^{f'(y^*)t}$

2.[1p]

An autonomous first order equation can have a solution that oscillates up and down.

The answer is: False
Correct

3.[2p]

For y'=3y-y2, what is the value of the stable equilibrium?

CorrectNot quite: 3

4.[3p]

A falling body obeys v'=g-(b/m)v2 with m/b=500 m and g=9.81 m s⁻². What is the terminal speed in metres per second?

CorrectNot quite: 70.0

5.[3p]

A logistic population has r=0.5 per year and K=800 tonnes. What is the largest constant harvest, in tonnes per year, that it can sustain?

CorrectNot quite: 100

6.[2p]

A logistic population has r=0.08 per year. What is the time constant, in years, of its approach to the carrying capacity?

CorrectNot quite: 12.5

7.[3p]

Which statements about the phase line are correct?

Select all that apply

Correct
Correct
Correct
The answer is: Equilibria are the roots of $f$, and no solution can cross one, Between consecutive equilibria a solution is monotone, An equilibrium with arrows pointing in from both sides is stable

8.[3p]

Why can a harvested fishery collapse with little warning as the catch is raised?

Correct
The answer is: The stable and unstable equilibria collide and vanish at a critical catch, leaving no equilibrium at all
The answer is: The stable and unstable equilibria collide and vanish at a critical catch, leaving no equilibrium at all
The answer is: The stable and unstable equilibria collide and vanish at a critical catch, leaving no equilibrium at all

9.[3p]

Match each equation to the character of its equilibrium at y=0.

  • y'=-2y

  • y'=2y

  • y'=y2

  • y'=-y3

  • unstable

  • stable

  • stable

  • semi-stable

Show the answer

y'=-2y: stable y'=2y: unstable y'=y2: semi-stable y'=-y3: stable