Sign in

Libre University uses your GitHub account. Signing in is only needed to sit a final test, so the score is kept on your profile.

Orbits

1.[3p]

A probe circles Mars at an altitude of 400 km. Taking GMM=4.283×1013 m³ s⁻² and a Martian radius of 3.390×106 m, what is its orbital speed in metres per second?

CorrectNot quite: 3362

2.[3p]

A satellite in low orbit is slowed by the thin atmosphere it passes through. What happens over the following weeks?

Correct
The answer is: It loses total energy, so its radius falls and its orbital speed rises
The answer is: It loses total energy, so its radius falls and its orbital speed rises
The answer is: It loses total energy, so its radius falls and its orbital speed rises

3.[2p]

Two orbits around the same star with the same semi-major axis but very different eccentricities have the same total energy.

Correct
The answer is: True

4.[2p]

A transfer orbit has a perigee radius of 7.0×106 m and an apogee radius of 4.2×107 m. What is its eccentricity?

CorrectNot quite: 0.714

5.[3p]

For that same orbit, what is the speed at perigee in metres per second, with GME=3.986×1014 m³ s⁻²?

CorrectNot quite: 9880

6.[3p]

Match each total energy to the shape of the resulting path.

  • Negative total energy

  • Zero total energy

  • Positive total energy

  • Negative total energy with zero eccentricity

  • a circle

  • a closed ellipse

  • a parabola, reaching infinity with no speed left

  • a hyperbola, escaping with speed to spare

Show the answer

Negative total energy: a closed ellipse Zero total energy: a parabola, reaching infinity with no speed left Positive total energy: a hyperbola, escaping with speed to spare Negative total energy with zero eccentricity: a circle

7.[3p]

Which of these are true of the vis viva equation v2=GM(2/r-1/a)?

Select all that apply

Correct
Correct
Correct
The answer is: Setting $r = a$ recovers the circular orbit speed, Letting $a$ grow without bound gives the escape speed at radius $r$, It gives the speed at any radius without needing the eccentricity

8.[2p]

Put the stages of a Hohmann transfer between two circular orbits in order.

  1. Burn in the low circular orbit, raising the far point of the path to the target radius

  2. Burn again on arrival, raising the near point so the orbit is circular

  3. Coast half an ellipse out to the target radius

Show the answer

b, a, c

9.[3p]

What is the 43 arcseconds per century in Mercury's perihelion advance?

Correct
The answer is: What is left of the observed advance once the equinoxes and the other planets are subtracted, which Newtonian gravity cannot account for
The answer is: What is left of the observed advance once the equinoxes and the other planets are subtracted, which Newtonian gravity cannot account for
The answer is: What is left of the observed advance once the equinoxes and the other planets are subtracted, which Newtonian gravity cannot account for