Periodicity
1.[2p] Mendeleev left gaps in his table rather than closing them up. Why does that matter more than the arrangement itself?
Mendeleev left gaps in his table rather than closing them up. Why does that matter more than the arrangement itself?
The answer is: A scheme that predicts the properties of unknown elements is a theory, not a catalogue
The answer is: A scheme that predicts the properties of unknown elements is a theory, not a catalogue
The answer is: A scheme that predicts the properties of unknown elements is a theory, not a catalogue
2.[2p] Moseley showed that the ordering variable is atomic number, not atomic weight. Which anomaly did that resolve?
Moseley showed that the ordering variable is atomic number, not atomic weight. Which anomaly did that resolve?
The answer is: Tellurium is heavier than iodine yet belongs before it
The answer is: Tellurium is heavier than iodine yet belongs before it
The answer is: Tellurium is heavier than iodine yet belongs before it
3.[1p] Atomic radius falls across a period. What is the reason?
Atomic radius falls across a period. What is the reason?
The answer is: rises while stays the same, so the shell is pulled in
The answer is: rises while stays the same, so the shell is pulled in
The answer is: rises while stays the same, so the shell is pulled in
4.[2p] The first ionisation energy of boron (801 kJ per mol) is lower than that of beryllium (899). Why?
The first ionisation energy of boron (801 kJ per mol) is lower than that of beryllium (899). Why?
The answer is: Boron's outermost electron is in a orbital, which penetrates the core less and is better shielded
The answer is: Boron's outermost electron is in a orbital, which penetrates the core less and is better shielded
The answer is: Boron's outermost electron is in a orbital, which penetrates the core less and is better shielded
5.[2p] Oxygen (1314 kJ per mol) is easier to ionise than nitrogen (1402). Why?
Oxygen (1314 kJ per mol) is easier to ionise than nitrogen (1402). Why?
The answer is: Oxygen's fourth electron must pair, and pairing costs repulsion energy that is repaid on removal
The answer is: Oxygen's fourth electron must pair, and pairing costs repulsion energy that is repaid on removal
The answer is: Oxygen's fourth electron must pair, and pairing costs repulsion energy that is repaid on removal
6.[2p] Put these isoelectronic ions in order of decreasing radius.
Put these isoelectronic ions in order of decreasing radius.
F⁻
Na⁺
N³⁻
Mg²⁺
Show the answer
n, f, na, mg
7.[1p] Fluorine has a more negative electron affinity than chlorine, because it sits higher in the group.
Fluorine has a more negative electron affinity than chlorine, because it sits higher in the group.
The answer is: False