Sets
1.[1p] .
.
Correct
The answer is: True
2.[3p] Let . Which statements are true?
Let . Which statements are true?
Select all that apply
Correct
Correct
The answer is: $1 \in A$, $\{1\} \subseteq A$, $\{2\} \in A$, $\varnothing \subseteq A$
Correct
The answer is: $1 \in A$, $\{1\} \subseteq A$, $\{2\} \in A$, $\varnothing \subseteq A$
Correct
The answer is: $1 \in A$, $\{1\} \subseteq A$, $\{2\} \in A$, $\varnothing \subseteq A$
3.[2p] Why is true for every set ?
Why is true for every set ?
Correct
The answer is: For every $x$ the hypothesis of "$x \in \varnothing \Rightarrow x \in A$" is false, so the conditional is vacuously true
The answer is: For every $x$ the hypothesis of "$x \in \varnothing \Rightarrow x \in A$" is false, so the conditional is vacuously true
The answer is: For every $x$ the hypothesis of "$x \in \varnothing \Rightarrow x \in A$" is false, so the conditional is vacuously true
4.[2p] Match each set to the condition for to belong to it, where complements are taken in a universe .
Match each set to the condition for to belong to it, where complements are taken in a universe .
, and
or
and
and
Show the answer
: or : and : and : , and
5.[2p] In the universe , let and . What is ?
In the universe , let and . What is ?
Correct
The answer is: $\{1, 2, 5, 6\}$
The answer is: $\{1, 2, 5, 6\}$
The answer is: $\{1, 2, 5, 6\}$
6.[2p] Put the lines of the proof that in order.
Put the lines of the proof that in order.
Then and .
If were in or in , it would be in , so and .
Hence and .
Let .
So , and since was arbitrary, the inclusion holds.
Show the answer
a, b, c, d, e
7.[1p] A set has elements. How many elements does have?
A set has elements. How many elements does have?
CorrectNot quite: 64
8.[2p] A set has elements. How many elements does have?
A set has elements. How many elements does have?
CorrectNot quite: 24
9.[2p] Applied to for a set , Russell's argument proves what?
Applied to for a set , Russell's argument proves what?
Correct
The answer is: $R_A \notin A$, so no set contains every set
The answer is: $R_A \notin A$, so no set contains every set
The answer is: $R_A \notin A$, so no set contains every set