Sets
1.[1p] .
.
The answer is: True
2.[3p] Let . Which statements are true?
Let . Which statements are true?
Select all that apply
The answer is: , , ,
The answer is: , , ,
The answer is: , , ,
3.[2p] Why is true for every set ?
Why is true for every set ?
The answer is: For every the hypothesis of "" is false, so the conditional is vacuously true
The answer is: For every the hypothesis of "" is false, so the conditional is vacuously true
The answer is: For every the hypothesis of "" is false, so the conditional is vacuously true
4.[2p] Match each set to the condition for to belong to it, where complements are taken in a universe .
Match each set to the condition for to belong to it, where complements are taken in a universe .
, and
or
and
and
Show the answer
: or : and : and : , and
5.[2p] In the universe , let and . What is ?
In the universe , let and . What is ?
The answer is:
The answer is:
The answer is:
6.[2p] Put the lines of the proof that in order.
Put the lines of the proof that in order.
Then and .
If were in or in , it would be in , so and .
Hence and .
Let .
So , and since was arbitrary, the inclusion holds.
Show the answer
a, b, c, d, e
7.[1p] A set has elements. How many elements does have?
A set has elements. How many elements does have?
8.[2p] A set has elements. How many elements does have?
A set has elements. How many elements does have?
9.[2p] Applied to for a set , Russell's argument proves what?
Applied to for a set , Russell's argument proves what?
The answer is: , so no set contains every set
The answer is: , so no set contains every set
The answer is: , so no set contains every set
10.[1p] Let and . How many elements does the symmetric difference have?
Let and . How many elements does the symmetric difference have?
11.[3p] For sets and , which of these conditions are equivalent to ?
For sets and , which of these conditions are equivalent to ?
Select all that apply
The answer is: , , ,
12.[2p] What is ?
What is ?
The answer is:
The answer is:
The answer is:
13.[2p] Which axiom of Zermelo and Fraenkel set theory prevents Russell's set from being formed?
Which axiom of Zermelo and Fraenkel set theory prevents Russell's set from being formed?
The answer is: Separation: a property may only carve a subset out of a set already given
The answer is: Separation: a property may only carve a subset out of a set already given
The answer is: Separation: a property may only carve a subset out of a set already given