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Sets

1.[1p]

{1,2,2}={2,1}.

Correct
The answer is: True

2.[3p]

Let A={1,{2}}. Which statements are true?

Select all that apply

Correct
Correct
The answer is: $1 \in A$, $\{1\} \subseteq A$, $\{2\} \in A$, $\varnothing \subseteq A$
Correct
The answer is: $1 \in A$, $\{1\} \subseteq A$, $\{2\} \in A$, $\varnothing \subseteq A$
Correct
The answer is: $1 \in A$, $\{1\} \subseteq A$, $\{2\} \in A$, $\varnothing \subseteq A$

3.[2p]

Why is ∅⊆A true for every set A?

Correct
The answer is: For every $x$ the hypothesis of "$x \in \varnothing \Rightarrow x \in A$" is false, so the conditional is vacuously true
The answer is: For every $x$ the hypothesis of "$x \in \varnothing \Rightarrow x \in A$" is false, so the conditional is vacuously true
The answer is: For every $x$ the hypothesis of "$x \in \varnothing \Rightarrow x \in A$" is false, so the conditional is vacuously true

4.[2p]

Match each set to the condition for x to belong to it, where complements are taken in a universe U.

  • A∪B

  • A∩B

  • A∖B

  • (A∪B)c

  • x∈U, x∉A and x∉B

  • x∈A or x∈B

  • x∈A and x∉B

  • x∈A and x∈B

Show the answer

A∪B: x∈A or x∈B A∩B: x∈A and x∈B A∖B: x∈A and x∉B (A∪B)c: x∈U, x∉A and x∉B

5.[2p]

In the universe U={1,2,3,4,5,6}, let A={1,2,3,4} and B={3,4,5}. What is Ac∪Bc?

Correct
The answer is: $\{1, 2, 5, 6\}$
The answer is: $\{1, 2, 5, 6\}$
The answer is: $\{1, 2, 5, 6\}$

6.[2p]

Put the lines of the proof that (A∪B)c⊆Ac∩Bc in order.

  1. Then x∈U and x∉A∪B.

  2. If x were in A or in B, it would be in A∪B, so x∉A and x∉B.

  3. Hence x∈Ac and x∈Bc.

  4. Let x∈(A∪B)c.

  5. So x∈Ac∩Bc, and since x was arbitrary, the inclusion holds.

Show the answer

a, b, c, d, e

7.[1p]

A set A has 6 elements. How many elements does P(A) have?

CorrectNot quite: 64

8.[2p]

A set A has 3 elements. How many elements does P(A)×A have?

CorrectNot quite: 24

9.[2p]

Applied to RA={x∈A:x∉x} for a set A, Russell's argument proves what?

Correct
The answer is: $R_A \notin A$, so no set contains every set
The answer is: $R_A \notin A$, so no set contains every set
The answer is: $R_A \notin A$, so no set contains every set