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Limits, proved

1.[2p]

Put the lines of the proof that 2n+3n+1→2 in order.

  1. Since ε was arbitrary, an→2.

  2. Let ε>0.

  3. Then |an-2|=1n+1<1n≤1N<ε.

  4. By the Archimedean property there is N∈ℕ with N>1ε.

  5. Let n≥N.

Show the answer

a, b, c, d, e

2.[2p]

For an=3n+1n+2 and L=3, what is the smallest N such that |an-3|<0.01 for every n≥N?

CorrectNot quite: 499

3.[1p]

For an=1n and L=0, what is the smallest N such that |an|<0.003 for every n≥N?

CorrectNot quite: 334

4.[1p]

In the proof that 1n→0, which step needs the Archimedean property?

Correct
The answer is: Finding a natural number $N$ with $N > \frac{1}{\varepsilon}$
The answer is: Finding a natural number $N$ with $N > \frac{1}{\varepsilon}$
The answer is: Finding a natural number $N$ with $N > \frac{1}{\varepsilon}$

5.[2p]

A proof that 3n+1n+2→3 says "take N=5ε". What would a careful reader object to?

Correct
The answer is: $\frac{5}{\varepsilon}$ is usually not a natural number, so it cannot serve as $N$
The answer is: $\frac{5}{\varepsilon}$ is usually not a natural number, so it cannot serve as $N$
The answer is: $\frac{5}{\varepsilon}$ is usually not a natural number, so it cannot serve as $N$

6.[2p]

Which of these are correct about proving that (-1)n diverges?

Select all that apply

Correct
Correct
Correct
The answer is: The proof must show the sequence converges to no real number $L$, so it starts with an arbitrary $L$, The prover chooses the tolerance, here $\varepsilon = 1$, For each $N$, one of the terms at positions $2N$ and $2N + 1$ lies at least $1$ from $L$
The answer is: The proof must show the sequence converges to no real number $L$, so it starts with an arbitrary $L$, The prover chooses the tolerance, here $\varepsilon = 1$, For each $N$, one of the terms at positions $2N$ and $2N + 1$ lies at least $1$ from $L$

7.[3p]

Match each theorem to the move its proof turns on.

  • Uniqueness of limits

  • Limit of a sum

  • Convergent sequences are bounded

  • Monotone convergence

  • the tolerance |L-M|2 and a contradiction

  • the supremum of the terms, from completeness

  • tolerance 1 and the finitely many earlier terms

  • tolerance ε2 for each sequence

Show the answer

Uniqueness of limits: the tolerance |L-M|2 and a contradiction Limit of a sum: tolerance ε2 for each sequence Convergent sequences are bounded: tolerance 1 and the finitely many earlier terms Monotone convergence: the supremum of the terms, from completeness

8.[1p]

Every bounded sequence of real numbers converges.

The answer is: False
Correct

9.[3p]

Which of these are true of the decimal truncations 1,1.4,1.41,1.414,… of 2?

Select all that apply

Correct
Correct
Correct
Correct
The answer is: Every term is rational and the sequence is increasing and bounded above, In $ℝ$ the sequence converges to $\sqrt{2}$, In $ℚ$ the sequence has no limit, In $ℚ$ the proof of monotone convergence breaks where it takes a supremum