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Functions

1.[1p]

The functions s:ℝ→ℝ and t:ℝ→[0,∞), both given by x↦x2, are the same function, since they have the same value at every real number.

The answer is: False
Correct

2.[1p]

Let s:ℝ→ℝ, s(x)=x2. What is the preimage s-1([1,4])?

Correct
The answer is: $[-2, -1] \cup [1, 2]$
The answer is: $[-2, -1] \cup [1, 2]$
The answer is: $[-2, -1] \cup [1, 2]$

3.[3p]

Let f:A→B be any function, S⊆A and T⊆B. Which statements are always true?

Select all that apply

Correct
Correct
The answer is: $f(f^{-1}(T)) \subseteq T$, $S \subseteq f^{-1}(f(S))$, If $f$ is surjective, then $f(f^{-1}(T)) = T$
The answer is: $f(f^{-1}(T)) \subseteq T$, $S \subseteq f^{-1}(f(S))$, If $f$ is surjective, then $f(f^{-1}(T)) = T$
Correct

4.[3p]

Match each function to its properties.

  • x↦3x+7 from ℝ to ℝ

  • n↦2n from ℕ to ℕ

  • x↦x2 from ℝ to [0,∞)

  • x↦x2 from ℝ to ℝ

  • neither injective nor surjective

  • bijective

  • injective, not surjective

  • surjective, not injective

Show the answer

x↦3x+7 from ℝ to ℝ: bijective n↦2n from ℕ to ℕ: injective, not surjective x↦x2 from ℝ to [0,∞): surjective, not injective x↦x2 from ℝ to ℝ: neither injective nor surjective

5.[2p]

The proof that x↦3x+7 is surjective on ℝ puts a=b-73. For the same rule from ℤ to ℤ, which step of that proof breaks down?

Correct
The answer is: Checking that $a$ belongs to the domain, since $\frac{b - 7}{3}$ need not be an integer
The answer is: Checking that $a$ belongs to the domain, since $\frac{b - 7}{3}$ need not be an integer
The answer is: Checking that $a$ belongs to the domain, since $\frac{b - 7}{3}$ need not be an integer

6.[2p]

Put the lines of the proof that if f:A→B, g:B→C and g∘f is surjective, then g is surjective, in order.

  1. Put b=f(a), which is an element of B.

  2. Since c was arbitrary, g is surjective.

  3. Since g∘f is surjective, there is a∈A with g(f(a))=c.

  4. Let c∈C.

  5. Then g(b)=g(f(a))=c.

Show the answer

a, b, c, d, e

7.[2p]

Functions f:A→B and g:B→A satisfy g∘f=idA, and nothing more is known. What follows?

Correct
The answer is: $f$ is injective
The answer is: $f$ is injective
The answer is: $f$ is injective

8.[1p]

How many functions are there from a set with 3 elements to a set with 5 elements?

CorrectNot quite: 125

9.[2p]

How many injective functions are there from a set with 3 elements to a set with 5 elements?

CorrectNot quite: 60