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Equivalence relations

1.[3p]

Which of these relations on ℤ are equivalence relations?

Select all that apply

Correct
Correct
Correct
The answer is: $a \sim b$ when $a \equiv b \pmod{7}$, $a \sim b$ when $a^2 = b^2$, $a \sim b$ when $a + b$ is even
The answer is: $a \sim b$ when $a \equiv b \pmod{7}$, $a \sim b$ when $a^2 = b^2$, $a \sim b$ when $a + b$ is even
The answer is: $a \sim b$ when $a \equiv b \pmod{7}$, $a \sim b$ when $a^2 = b^2$, $a \sim b$ when $a + b$ is even

2.[2p]

Match each relation on ℝ to the property it lacks.

  • x≤y

  • |x-y|≤1

  • xy>0

  • x-y∈ℤ

  • reflexive

  • symmetric

  • transitive

  • none, it is an equivalence relation

Show the answer

x≤y: symmetric |x-y|≤1: transitive xy>0: reflexive x-y∈ℤ: none, it is an equivalence relation

3.[2p]

What is wrong with the argument "if a∼b then b∼a by symmetry, so a∼a by transitivity, hence every symmetric and transitive relation is reflexive"?

Correct
The answer is: It assumes some $b$ with $a \sim b$ exists, and for some $a$ there may be none
The answer is: It assumes some $b$ with $a \sim b$ exists, and for some $a$ there may be none
The answer is: It assumes some $b$ with $a \sim b$ exists, and for some $a$ there may be none

4.[1p]

How many relations are there on a set with 3 elements?

CorrectNot quite: 512

5.[2p]

How many equivalence relations are there on the set {1,2,3,4}?

CorrectNot quite: 15

6.[1p]

Which set is the congruence class [2] modulo 3?

Correct
The answer is: $\{ \ldots, -4, -1, 2, 5, 8, \ldots \}$
The answer is: $\{ \ldots, -4, -1, 2, 5, 8, \ldots \}$
The answer is: $\{ \ldots, -4, -1, 2, 5, 8, \ldots \}$

7.[2p]

Put the lines of the proof that the relation (a,b)∼(c,d) when ad=bc, on pairs with nonzero second coordinate, is transitive in order.

  1. Let (a,b)∼(c,d) and (c,d)∼(e,f), so ad=bc and cf=de.

  2. Multiplying the first equation by f gives adf=bcf.

  3. Substituting cf=de gives adf=bde.

  4. Since d≠0, af=be, that is, (a,b)∼(e,f).

  5. So d(af-be)=0.

Show the answer

a, b, c, d, e

8.[2p]

In building ℚ from pairs (a,b) with (a,b)∼(c,d) when ad=bc, why must the pair (0,0) be excluded?

Correct
The answer is: It would be related to every pair, and transitivity would fail
The answer is: It would be related to every pair, and transitivity would fail
The answer is: It would be related to every pair, and transitivity would fail

9.[3p]

Which of these rules are well defined?

Select all that apply

Correct
Correct
Correct
The answer is: $[a] + [b] = [a + b]$ on congruence classes modulo $n$, $[(a, b)] \mapsto [(a^2, b^2)]$ on $ℚ$, The congruence class of $a$ modulo $6$ sent to the class of $a$ modulo $3$
The answer is: $[a] + [b] = [a + b]$ on congruence classes modulo $n$, $[(a, b)] \mapsto [(a^2, b^2)]$ on $ℚ$, The congruence class of $a$ modulo $6$ sent to the class of $a$ modulo $3$
The answer is: $[a] + [b] = [a + b]$ on congruence classes modulo $n$, $[(a, b)] \mapsto [(a^2, b^2)]$ on $ℚ$, The congruence class of $a$ modulo $6$ sent to the class of $a$ modulo $3$