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Direct proof and proof by cases

1.[1p]

How should a direct proof of "for every integer n, if n is odd then n2 is odd" begin?

Correct
The answer is: Let $n$ be an odd integer.
The answer is: Let $n$ be an odd integer.
The answer is: Let $n$ be an odd integer.

2.[2p]

Which of these statements are true?

Select all that apply

Correct
The answer is: $3 \mid 12$, $-4 \mid 12$, $7 \mid 0$, $1 \mid 13$
Correct
Correct
The answer is: $3 \mid 12$, $-4 \mid 12$, $7 \mid 0$, $1 \mid 13$
Correct

3.[2p]

Put the lines of this proof that if a∣b and b∣c then a∣c in order.

  1. By definition, b=ak and c=bm for some integers k and m.

  2. Let a, b and c be integers with a∣b and b∣c.

  3. Substituting, c=(ak)m=a(km).

  4. Since k and m are integers, so is km.

  5. So c is a times an integer, and by definition a∣c.

Show the answer

a, b, c, d, e

4.[1p]

A proof of |x+y|≤|x|+|y| that treats only the case x≥0,y≥0 and the case x<0,y<0 is complete.

The answer is: False
Correct

5.[2p]

The proof that every odd square is one more than a multiple of 8 writes n=2k+1 and gets n2=4(k2+k)+1. What finishes it?

Correct
The answer is: The earlier result that $k^2 + k$ is even for every integer $k$
The answer is: The earlier result that $k^2 + k$ is even for every integer $k$
The answer is: The earlier result that $k^2 + k$ is even for every integer $k$

6.[3p]

Match each claim to the method its proof in the lesson used.

  • If a∣b and b∣c then a∣c

  • n2+n is even for every integer n

  • |x+y|≤|x|+|y| for all reals

  • For every k there are k consecutive non-primes

  • Some irrational a and b have ab rational

  • cases on signs

  • a non-constructive existence proof

  • a constructive existence proof

  • a direct proof from the definition

  • cases on parity

Show the answer

If a∣b and b∣c then a∣c: a direct proof from the definition n2+n is even for every integer n: cases on parity |x+y|≤|x|+|y| for all reals: cases on signs For every k there are k consecutive non-primes: a constructive existence proof Some irrational a and b have ab rational: a non-constructive existence proof

7.[3p]

The proof that some irrational a and b give ab rational considers 22. Which of these are true of it?

Select all that apply

Correct
Correct
The answer is: It shows that one of two pairs works without saying which, It uses the fact that every real number is rational or irrational, It relies on $\sqrt{2}$ being irrational
The answer is: It shows that one of two pairs works without saying which, It uses the fact that every real number is rational or irrational, It relies on $\sqrt{2}$ being irrational
Correct

8.[2p]

The constructive proof takes N=(k+1)! and the numbers N+2 to N+(k+1). For k=5, which run of non-primes does it produce?

Correct
The answer is: $722$ to $726$
The answer is: $722$ to $726$
The answer is: $722$ to $726$

9.[2p]

Why does a direct proof of "if n2 is even then n is even" stall?

Correct
The answer is: The hypothesis $n^2 = 2k$ gives $n = \pm\sqrt{2k}$, which is not visibly twice an integer
The answer is: The hypothesis $n^2 = 2k$ gives $n = \pm\sqrt{2k}$, which is not visibly twice an integer
The answer is: The hypothesis $n^2 = 2k$ gives $n = \pm\sqrt{2k}$, which is not visibly twice an integer