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Counting the infinite

1.[1p]

What does |A|≤|B| mean for sets A and B?

Correct
The answer is: There is an injection $A \to B$
The answer is: There is an injection $A \to B$
The answer is: There is an injection $A \to B$

2.[1p]

The set ℕ∖{1} is the same size as ℕ.

Correct
The answer is: True

3.[1p]

The bijection f:ℕ→ℤ has f(n)=n2 for even n and f(n)=1-n2 for odd n. Which natural number n has f(n)=-4?

CorrectNot quite: 9

4.[2p]

Evaluate the pairing function p(m,n)=(m+n-2)(m+n-1)2+m at (m,n)=(4,7).

CorrectNot quite: 49

5.[3p]

Which of these sets are countable?

Select all that apply

Correct
Correct
Correct
Correct
The answer is: $ℤ$, $ℕ \times ℕ$, $ℚ$, $ℤ \times ℤ$
The answer is: $ℤ$, $ℕ \times ℕ$, $ℚ$, $ℤ \times ℤ$
The answer is: $ℤ$, $ℕ \times ℕ$, $ℚ$, $ℤ \times ℤ$

6.[2p]

Match each result to the idea that proves it.

  • ℤ is countable

  • ℕ×ℕ is countable

  • ℚ is countable

  • (0,1) is uncountable

  • |A|<|P(A)|

  • the set of elements not in their own image

  • change the nth digit of the nth number

  • alternate positive and non-positive values by parity

  • inject into ℕ×ℕ and apply Schröder and Bernstein

  • list the pairs diagonal by diagonal

Show the answer

ℤ is countable: alternate positive and non-positive values by parity ℕ×ℕ is countable: list the pairs diagonal by diagonal ℚ is countable: inject into ℕ×ℕ and apply Schröder and Bernstein (0,1) is uncountable: change the nth digit of the nth number |A|<|P(A)|: the set of elements not in their own image

7.[2p]

In the diagonal argument for (0,1), why are the new digits chosen from 4 and 5 rather than any digit different from the diagonal one?

Correct
The answer is: So the new number has only one decimal expansion and cannot be a listed number written another way
The answer is: So the new number has only one decimal expansion and cannot be a listed number written another way
The answer is: So the new number has only one decimal expansion and cannot be a listed number written another way

8.[2p]

Put the lines of the proof that no function F:A→P(A) is surjective in order.

  1. Otherwise d∉D, so d∉F(d), which is the condition for d∈D.

  2. Suppose D=F(d) for some d∈A.

  3. Let D={a∈A:a∉F(a)}, a subset of A.

  4. Both cases are contradictions, so D is not a value of F.

  5. If d∈D, then d∉F(d)=D by the definition of D.

Show the answer

a, b, c, d, e

9.[1p]

What is known about the continuum hypothesis, that every infinite set of reals is either countable or the same size as ℝ?

Correct
The answer is: It can be neither proved nor disproved from the usual axioms of set theory
The answer is: It can be neither proved nor disproved from the usual axioms of set theory
The answer is: It can be neither proved nor disproved from the usual axioms of set theory