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Counting the infinite

1.[1p]

What does |A|≤|B| mean for sets A and B?

Correct

The answer is: There is an injection A→B

The answer is: There is an injection A→B

The answer is: There is an injection A→B

2.[1p]

The set ℕ∖{1} is the same size as ℕ.

Correct

The answer is: True

3.[1p]

The bijection f:ℕ→ℤ has f(n)=n2 for even n and f(n)=1−n2 for odd n. Which natural number n has f(n)=−4?

CorrectNot quite: 9

4.[2p]

Evaluate the pairing function p(m,n)=(m+n−2)(m+n−1)2+m at (m,n)=(4,7).

CorrectNot quite: 49

5.[3p]

Which of these sets are countable?

Select all that apply

Correct
Correct
Correct
Correct

The answer is: ℤ, ℕ×ℕ, ℚ, ℤ×ℤ

The answer is: ℤ, ℕ×ℕ, ℚ, ℤ×ℤ

The answer is: ℤ, ℕ×ℕ, ℚ, ℤ×ℤ

6.[2p]

Match each result to the idea that proves it.

  • ℤ is countable

  • ℕ×ℕ is countable

  • ℚ is countable

  • (0,1) is uncountable

  • |A|<|P(A)|

  • the set of elements not in their own image

  • change the nth digit of the nth number

  • inject into ℕ×ℕ, and so into ℕ

  • alternate positive and non-positive values by parity

  • list the pairs diagonal by diagonal

Show the answer

ℤ is countable: alternate positive and non-positive values by parity ℕ×ℕ is countable: list the pairs diagonal by diagonal ℚ is countable: inject into ℕ×ℕ, and so into ℕ (0,1) is uncountable: change the nth digit of the nth number |A|<|P(A)|: the set of elements not in their own image

7.[2p]

In the diagonal argument for (0,1), why are the new digits chosen from 4 and 5 rather than any digit different from the diagonal one?

Correct

The answer is: So the new number has only one decimal expansion and cannot be a listed number written another way

The answer is: So the new number has only one decimal expansion and cannot be a listed number written another way

The answer is: So the new number has only one decimal expansion and cannot be a listed number written another way

8.[2p]

Put the lines of the proof that no function F:A→P(A) is surjective in order.

  1. Otherwise d∉D, so d∉F(d), which is the condition for d∈D.

  2. Suppose D=F(d) for some d∈A.

  3. Let D={a∈A:a∉F(a)}, a subset of A.

  4. Both cases are contradictions, so D is not a value of F.

  5. If d∈D, then d∉F(d)=D by the definition of D.

Show the answer

a, b, c, d, e

9.[1p]

What is known about the continuum hypothesis, that every infinite set of reals is either countable or the same size as ℝ?

Correct

The answer is: It can be neither proved nor disproved from the usual axioms of set theory

The answer is: It can be neither proved nor disproved from the usual axioms of set theory

The answer is: It can be neither proved nor disproved from the usual axioms of set theory

10.[1p]

The map F(m,n)=2m−1(2n−1) is a bijection ℕ×ℕ→ℕ. Which natural number is F(3,2)?

CorrectNot quite: 12

11.[1p]

A union of countably many countable sets is countable.

Correct

The answer is: True

12.[2p]

Why must transcendental numbers exist?

Correct

The answer is: The algebraic numbers are countable and ℝ is not

The answer is: The algebraic numbers are countable and ℝ is not

The answer is: The algebraic numbers are countable and ℝ is not

13.[3p]

Which of these sets have the same size as ℝ?

Select all that apply

Correct
Correct
Correct
Correct

The answer is: (0,1), P(ℕ), ℝ×ℝ, The set of irrational numbers

The answer is: (0,1), P(ℕ), ℝ×ℝ, The set of irrational numbers

14.[2p]

What does the Schröder and Bernstein theorem say?

Correct

The answer is: If there are injections A→B and B→A, then there is a bijection A→B

The answer is: If there are injections A→B and B→A, then there is a bijection A→B

The answer is: If there are injections A→B and B→A, then there is a bijection A→B