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Outcomes and events

1.[2p]

Why is the sample space for two dice usually taken as the 36 ordered pairs rather than the 11 possible totals?

Correct
The answer is: Only the pairs are interchangeable, so only they can be counted as equally likely
The answer is: Only the pairs are interchangeable, so only they can be counted as equally likely
The answer is: Only the pairs are interchangeable, so only they can be counted as equally likely

2.[2p]

Match each phrase to the set operation it becomes.

  • A or B

  • A and B

  • not A

  • A but not B

  • intersection

  • complement

  • union

  • difference

Show the answer

A or B: union A and B: intersection not A: complement A but not B: difference

3.[2p]

Which axiom is used to prove that P(Ac)=1-P(A)?

Correct
The answer is: Additivity for disjoint events, applied to $A$ and $A^c$, whose union is $\Omega$
The answer is: Additivity for disjoint events, applied to $A$ and $A^c$, whose union is $\Omega$
The answer is: Additivity for disjoint events, applied to $A$ and $A^c$, whose union is $\Omega$

4.[2p]

P(A)=0.6, P(B)=0.5 and P(AB)=0.2. Find P(AB).

CorrectNot quite: 0.9

5.[3p]

A whole number is drawn at random from 1 to 1000. What is the probability that it is divisible by 2, by 3 or by 5?

CorrectNot quite: 0.734

6.[1p]

The union bound P(AB)P(A)+P(B) requires A and B to be disjoint.

The answer is: False
Correct

7.[2p]

A die is loaded so that P(6)=0.25 and the other five faces are equally likely. What is the probability of rolling an even number?

CorrectNot quite: 0.55

8.[3p]

An event has probability zero. What does that establish?

Correct
The answer is: Nothing about whether it can occur: on an infinite sample space, possible events can have probability zero
The answer is: Nothing about whether it can occur: on an infinite sample space, possible events can have probability zero
The answer is: Nothing about whether it can occur: on an infinite sample space, possible events can have probability zero

9.[2p]

Put these results in the order the lesson derives them, each using the ones before it.

  1. P(A)P(B) when AB, from splitting B in two

  2. P(AB)=P(A)+P(B)-P(AB)

  3. P(A1An)P(A1)++P(An)

  4. P(Ac)=1-P(A), from additivity on A and Ac

Show the answer

a, b, c, d