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Reaction mechanisms

1.[2p]

For which kind of reaction can the rate law be written down directly from the equation?

Correct
The answer is: An elementary step, where order equals molecularity
The answer is: An elementary step, where order equals molecularity
The answer is: An elementary step, where order equals molecularity

2.[1p]

A rate law that fits a proposed mechanism proves that the mechanism is correct.

The answer is: False
Correct

3.[3p]

The observed rate law for N+CONO+C above 500 K is v=k[N]2. Why does carbon monoxide not appear?

Correct
The answer is: It is consumed only in a fast step after the rate determining one
The answer is: It is consumed only in a fast step after the rate determining one
The answer is: It is consumed only in a fast step after the rate determining one

4.[2p]

What does the steady state approximation assume?

Correct
The answer is: A reactive intermediate is destroyed as fast as it is formed, so its concentration barely changes
The answer is: A reactive intermediate is destroyed as fast as it is formed, so its concentration barely changes
The answer is: A reactive intermediate is destroyed as fast as it is formed, so its concentration barely changes

5.[3p]

An enzyme has KM=5.0×10-5 mol dm⁻³ and vmax=2.0×10-3 mol dm⁻³ s⁻¹. What is the rate, in mol dm⁻³ s⁻¹, at a substrate concentration of 1.0×10-3 mol dm⁻³?

CorrectNot quite: 0.0019

6.[2p]

For that same enzyme, at what substrate concentration, in mol dm⁻³, is the rate exactly half of vmax?

CorrectNot quite: 0.00005

7.[2p]

An elementary step has kf=1.6×10-2 and kr=2.95×10-4 in the same units. What is its equilibrium constant?

CorrectNot quite: 54.2

8.[2p]

Put the stages of a chain reaction in the order they occur.

  1. Propagation, in which a carrier is consumed and another produced

  2. Termination, in which carriers are destroyed

  3. Initiation, in which the first carriers are created

Show the answer

b, a, c

9.[3p]

Which statements about mechanisms are correct?

Select all that apply

Correct
Correct
Correct
The answer is: The steps must sum to the overall balanced equation, Termolecular steps are possible but rare, and steps of higher molecularity are not proposed, An intermediate is a real species, while a transition state is a maximum on a path