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Circular dynamics

1.[2p]

A level bend has radius 50 m and μs=0.70. What is the fastest speed a car can take it, in metres per second?

CorrectNot quite: 18.5

2.[3p]

A car takes a level bend too fast and leaves the road on the outside. What is the correct description?

Correct
The answer is: The friction available fell short of $mv^2/r$, so the car followed a path of larger radius than the bend
The answer is: The friction available fell short of $mv^2/r$, so the car followed a path of larger radius than the bend
The answer is: The friction available fell short of $mv^2/r$, so the car followed a path of larger radius than the bend

3.[3p]

At what angle, in degrees, must a bend of radius 150 m be banked so that a car at 25 m s⁻¹ needs no friction?

CorrectNot quite: 23.0

4.[2p]

What is the minimum speed at the top of a vertical loop of radius 12 m, in metres per second?

CorrectNot quite: 10.85

5.[1p]

The minimum speed at the top of a vertical loop depends on the mass of the body going round it.

The answer is: False
Correct

6.[3p]

A bob on a 1.5 m string swings as a conical pendulum at 25° to the vertical. What is the period, in seconds?

CorrectNot quite: 2.34

7.[3p]

Which of these are true of the fictitious forces used inside a rotating frame?

Select all that apply

Correct
Correct
Correct
The answer is: They have no identifiable agent exerting them, They have no third law partner, They disappear when the problem is redone in an inertial frame

8.[3p]

Match each circular motion problem to the force that supplies the centripetal requirement.

  • Car on a level bend

  • Car on a frictionless banked bend

  • Conical pendulum

  • Ball at the top of a vertical loop on a track

  • the horizontal component of the normal force

  • the weight plus the track's inward push

  • the horizontal component of the string tension

  • friction from the road

Show the answer

Car on a level bend: friction from the road Car on a frictionless banked bend: the horizontal component of the normal force Conical pendulum: the horizontal component of the string tension Ball at the top of a vertical loop on a track: the weight plus the track's inward push

9.[3p]

A 0.50 kg stone is whirled in a vertical circle of radius 0.80 m and passes the lowest point at 6.0 m s⁻¹. What is the string tension there, in newtons?

CorrectNot quite: 27.4