Limits
1.[3p] In the definition of , which order do the two tolerances come in?
In the definition of , which order do the two tolerances come in?
Correct
The answer is: The output tolerance is named first, and the input tolerance may depend on it
The answer is: The output tolerance is named first, and the input tolerance may depend on it
The answer is: The output tolerance is named first, and the input tolerance may depend on it
2.[2p] The value of can be found without knowing anything about .
The value of can be found without knowing anything about .
Correct
The answer is: True
3.[2p] Evaluate .
Evaluate .
CorrectNot quite: 12
4.[3p] Evaluate .
Evaluate .
CorrectNot quite: 0.25
5.[2p] Evaluate .
Evaluate .
CorrectNot quite: 0.6
6.[2p] Why is called an indeterminate form?
Why is called an indeterminate form?
Correct
The answer is: Because the form alone determines nothing: limits of that shape can come out to any value or to none
The answer is: Because the form alone determines nothing: limits of that shape can come out to any value or to none
The answer is: Because the form alone determines nothing: limits of that shape can come out to any value or to none
7.[3p] Match each limit as approaches to how it behaves.
Match each limit as approaches to how it behaves.
the limit is zero, by squeezing
the values oscillate forever
the values exceed every bound
the two sides disagree
Show the answer
: the two sides disagree : the values exceed every bound : the values oscillate forever : the limit is zero, by squeezing
8.[3p] Which of these are correct?
Which of these are correct?
Select all that apply
Correct
Correct
Correct
The answer is: $\lim_{x \to a} P(x) = P(a)$ for every polynomial $P$, Writing $\lim_{x \to 0} 1/x^2 = \infty$ is shorthand for a way of not existing, A two-sided limit exists exactly when both one-sided limits exist and agree
9.[2p] The squeeze theorem concludes that has limit at when
The squeeze theorem concludes that has limit at when
Correct
The answer is: $f$ is trapped between two functions that both have limit $L$ there
The answer is: $f$ is trapped between two functions that both have limit $L$ there
The answer is: $f$ is trapped between two functions that both have limit $L$ there