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Change of variables

1.[1p]

Which area element converts a double integral to polar coordinates?

Correct

The answer is: dA=rdrdθ

The answer is: dA=rdrdθ

The answer is: dA=rdrdθ

2.[2p]

A thin disc of radius 3 has surface density ρ=x2+y2. Find its mass, to two decimal places.

CorrectNot quite: 56.55

3.[2p]

Evaluate ∬A(x2+y2)dA over the annulus 4≤x2+y2≤9, to two decimal places.

CorrectNot quite: 102.10

4.[2p]

Evaluate ∬QydA, where Q is the quarter of the disc x2+y2≤9 lying in the first quadrant.

CorrectNot quite: 9

5.[2p]

Given that ∫−∞∞e−x2dx=π, evaluate ∫−∞∞e−4x2dx, to four decimal places.

CorrectNot quite: 0.8862

6.[2p]

Find the Jacobian ∂x∂u∂y∂v−∂x∂v∂y∂u of the substitution x=u2−v2, y=2uv at the point (u,v)=(1,2).

CorrectNot quite: 20

7.[2p]

Find the area enclosed by the ellipse x216+y29=1, to two decimal places.

CorrectNot quite: 37.70

8.[3p]

Let R be the region bounded by the lines x+y=0, x+y=4, x−y=0 and x−y=2. Evaluate ∬R(x+y)dA.

CorrectNot quite: 8

9.[3p]

Which of these statements about the Jacobian J of a substitution x=x(u,v), y=y(u,v) are true?

Select all that apply

Correct
Correct
Correct

The answer is: Near each point, the substitution multiplies small areas by |J|, For polar coordinates, J=r, For a linear substitution, J is the same at every point

The answer is: Near each point, the substitution multiplies small areas by |J|, For polar coordinates, J=r, For a linear substitution, J is the same at every point