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Flow work and the energy equation

1.[2p]

Why does enthalpy rather than internal energy appear in the energy balance for a stream crossing a port?

Correct
The answer is: The fluid behind must do work $pv$ per kilogram to push it across, and $u + pv$ is enthalpy
The answer is: The fluid behind must do work $pv$ per kilogram to push it across, and $u + pv$ is enthalpy
The answer is: The fluid behind must do work $pv$ per kilogram to push it across, and $u + pv$ is enthalpy

2.[2p]

Steam at 3 MPa has v=0.09056 m³/kg. What is the flow work per kilogram at that port, in kJ/kg?

CorrectNot quite: 271.7

3.[2p]

At a turbine exhaust the steam has h=2263.5 kJ/kg, p=10 kPa and v=12.71 m³/kg. What is its internal energy, in kJ/kg?

CorrectNot quite: 2136.4

4.[2p]

The work term W˙ in the steady-flow energy equation includes the flow work at the ports.

The answer is: False
Correct

5.[3p]

Steam enters a turbine at h1=3116.1 kJ/kg and 45 m/s and leaves at h2=2263.5 kJ/kg and 200 m/s, adiabatically. What is the work per kilogram, in kJ/kg?

CorrectNot quite: 833.6

6.[3p]

Which terms may usually be deleted from the steady-flow energy equation for a well-lagged turbine at pipe velocities?

Select all that apply

Correct
Correct
The answer is: The heat transfer term, The potential energy term
The answer is: The heat transfer term, The potential energy term

7.[3p]

A compressor takes 0.50 kg/s of air and raises its enthalpy by 293.5 kJ/kg, while losing 15 kW from its casing. What shaft power does it need, in kW?

CorrectNot quite: 161.7

8.[2p]

Match each velocity to its kinetic energy per kilogram, in kJ/kg.

  • 45 m/s

  • 100 m/s

  • 200 m/s

  • 450 m/s

  • 20

  • 101

  • 5.0

  • 1.01

Show the answer

45 m/s: 1.01 100 m/s: 5.0 200 m/s: 20 450 m/s: 101

9.[2p]

What can the steady-flow energy equation not tell you about a turbine?

Correct
The answer is: How much work it will actually produce, since the exit state is an input rather than an output
The answer is: How much work it will actually produce, since the exit state is an input rather than an output
The answer is: How much work it will actually produce, since the exit state is an input rather than an output